first derivative of 5.5x^.6/x-285/x-.55squareroot of "x"/x
My apologies for not thoroughly reading your first post. Do you have this so far? \[1/(500-0)\int\limits_{0}^{500}(R(x)-C(x))dx\]
huh? =/ we haven't gotten to that yet...
My bad again for taking it too far :) Do you have this? (R(x) - C(x)) / x
So you got the average profit already, now you are looking for the marginal?
Then it should be (R(500) - C(500)) / 500 I don't have each of the functions to calculate. You shouldn't need the derivative unless you are looking for marginal.
here's the question: Find the rate at which the average profit is changing when 500 bottles of apple juice have been produced and sold. The R(x)= 5.5x^.6 and C(x)=385+.55squareroot of "x"
\[d/dx(5.5x ^{-.4}-385x ^{-1}+.55x ^{-.5} )\]Correct?
wait OOPS its 285. and 285 doesn't have an "x"
and yeah for the other numbers I got the same exact derivative as you
This should be the derivative.\[P \prime(x)=(-.4)(5.5)x ^{-1.4}-(-1)(285)x ^{-2}+(-.5)(.55)x ^{-1.5}\]
we're on the same page up to there.. :) so from there evaluate it at 500 right?
That's what it should be, correct.
hmm ok lemme give it a shot :)
so to make it easier I should make the negative exponents denominators right to make em positive? (while evaluating)
If you prefer. It will evaluate the same way. Are you using a TI calculator?
I am and apparently i'm doing something wrong! My answers is wrong -.-
*answer is
0.00075 using significant figures
OMG! Thank you :( imma work to see where my calcualtions r going wrong
On your calculator: (-2.2)500^(-1.4)+(285)500^(-2)-(.275)500^(-1.5)
yeah I just plugged in the whole thing and I got the same answer :) THANK YOU!!!!!
I've not got to mess with calculus in a while, so if you want to be a 'fan', I would love to help you as you move through the semester.
absolutely! your personality and your technique are perfect :) I get it when u explain it! Do u mind if I ask you for another question?
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