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find the polynomial function with leading oefficient 2, degree 3, with -2, 1, and 4 as zeros
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how do i do it?
\[2(x+2)(x-1)(x-4)\]
y=2(x+2)(x-1)(x-4)
i know that the answer is 2x^3 -6x^2 -12x +16 but how do i get that
Those zeros (-2, 1, 4), when plugged into the x's, should make the polynomial 0. You get that by multiplying 2 with (x+2) with (x-1) with (x-4).
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do you understand what it means to BE a zero of a polynomial?
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