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\[\int\limits\limits_{0}^{∞} x^2e^{-2y|x|}dx = \left[ 2/(2y)^{3} \right] (\lim 0,∞)\] \ can someone explaine this
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please disregard the (lim 0 ,∞) bit
First, you can drop the absolute value signs as x is non-negative in the domain of integration. Then integrate by parts twice. E.g., first time u' = exp(-xy), v = x^2 then you'll need to integrate and third time and get the result.
make that u' = exp(-2xy)
integration by parts, three times, ...bother. well at least i know it will work. thanks
the third time isn't by parts -- you'll see.
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