how do you solve this system of linear equations? x+y=240 18x+12y+3120
=3120*
deja vu
id assume the way youd solve it as you do any system of equations
but i dont know how to do any systems of equations...
you should get \[x = 40,\ \ y = 200\]
then i would advise you to go back and review the section that teaches you those methods before trying to learn how to actually apply those methods
You have 3 options to solving systems of linear equations (with 2 variables x and y): graphing substitution elimination
but, i learned this in algebra 1, and now im in algebra 2 and forgot
thats a contradiction; if you learned it, then you would know it :)
there are many methods to solving systems of equations; some more labor intensive than others
the main objective to understand is that a solution means that when x and y have solid values; that they will produce the desired results
but it was in 7th grade now im in 9th and i need one of which i could show work.
these equation can be graphed by 2 lines; and where they cross is where the solution to the system is
so where they cross will be an ordered pair tho
yes, x = ? and y=? :)
x = 40 and y = 200
i would go after elimination; which is simply multiplying the top by -18 and adding the 2 together
ohhhhhhhhhhhhhhhhhhhhh.
x + y =240 ; *-18 18x+12y =3120 -18x -18y =240(-18) 18x +12y =3120 ------------------- -6y = 3120 - 240(-18) y = (3120 - 240(-18))/-6
i get y = -1240 that way tho
oh, i subtracted the right side instead of adding lol
y = (3120 + 240(-18))/-6 = 200 :)
thanks
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