How do you convert a 3D parameterization into (i,j,k) form?

Question

amistre64 · Answer

xi+yj+zk

amistre64 · Answer

if i understand the question that is

anonymous · Answer

I have a line x=(t+1,2t+2,3t+3) and I want to turn it into ijk

amistre64 · Answer

(t+1) i + (2t+2) j + (3t+3) k

amistre64 · Answer

or dp we omit the given reference point?

amistre64 · Answer

your vector to the point is t<1,2,3>

anonymous · Answer

but I want to do a cross product of two lines in that parametric form so I wanted to turn them into rectangular or something or the like.

anonymous · Answer

Could I use the parametric form?

amistre64 · Answer

show me both lines so that i can recall what it is i need to remember :)

amistre64 · Answer

to cross 2 lines you just need the vector components

amistre64 · Answer

the vector components are the coeffs of the variable

amistre64 · Answer

this one has a vector or <1,2,3>  and you other line is?

amistre64 · Answer

|dw:1316897118810:dw|

anonymous · Answer

(8t+1,2-t,-t+3) is the other line.
And I want to find a cross product or the two so I can find a plane that contains both of them eventually.

amistre64 · Answer

right .... the cross is the normal of the plane

anonymous · Answer

and I would find the difference of the two vectors then dot it with the norm, eh?

amistre64 · Answer

(8t+1,2-t,-t+3)|dw:1316897201150:dw|