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Solve v^3+4v^2-4v-16=0
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v=+2, -2 or -4, factor by grouping
How do you factor it though?
\[v^3 + 4v^2 - 4v - 16 = 0\], right??
v squared comes out of first two terms
- 4 comes out of last two
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this makes a (v+4) in the new terms created
I have v^2(v+4)-4(v+4)=0 then Idk what to do.
ok now do you see that (v+4) is in both terms, factor it out so you have (v+4)(v^2-4)
Oh! Ok. Thanks :)
sure
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