Question

Evaluate the indefinite integral: ln(7x)dx.

Answer 1

(x(log(7x)-1)+C

Answer 2

it can be reduced to integral(t*e^t/7 dt) and apply integration of products rule to get (t-1)e^t/7+Constant of integration.

Answer 3

i tend to see it as int by parts

Answer 4

it is int by parts

Answer 5

it is by parts

Answer 6

\[\int ln(7x)dx=x\ ln(7x)-\int {\frac{7x^2}{27x}} dx\]
\[\int ln(7x)dx=x\ ln(7x)-\int {\frac{x}{2}} dx\]
maybe

Answer 7

i misplaced a few things lol

Answer 8

\[\int\limits_{}^{}(\ln(7)+\ln(x)) dx=\ln(7) \cdot x+(x \ln(x)-\int\limits_{}^{}1 dx)+C=\ln(7) \cdot x+x \ln(x)-x+C\]

Answer 9

\[\int ln(7x)dx=x(v)\ ln(7x)(u)-\int {x(v)\frac{1}{x}(du)} dx\]
\[\int ln(7x)dx=x\ ln(7x)-\int {x\frac{1}{x}} dx\]
\[\int ln(7x)dx=x\ ln(7x)-\int dx\]

Answer 10

\[\int ln(7x)dx=x\ ln(7x)-x+C\] dbl chk with a derivative of it tho

Answer 11

looks good amistre but i think
it is easier to write
ln(7x) as ln(7)+ln(x) then integrate

Answer 12

your right, but i tend to do my math like a do my women :) in the end, aint nobody happy

Answer 13

lol