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Mathematics 14 Online
OpenStudy (anonymous):

Is it possible to use the dot product with a vector and magnitude? ie. r dot |r|

OpenStudy (anonymous):

no

OpenStudy (anonymous):

do you just distribute?

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

no, because x dot y is defined only when x and y are both vectors

OpenStudy (anonymous):

a vector times a scalar is distribution

OpenStudy (anonymous):

right but a vector dot scalar is distribution?

jimthompson5910 (jim_thompson5910):

If the vector x = <a, b> and | x | = c for some scalar c, then |x|*x = c*<a,b> = <ca, cb>

OpenStudy (anonymous):

so what would be the outcome of r dot r'(0)??? trying to figure out what r is because i know i have the right answer but this program we use says it isn't

OpenStudy (anonymous):

ahhhh so you can then

jimthompson5910 (jim_thompson5910):

r looks like a function in polar coordinates

jimthompson5910 (jim_thompson5910):

or it's probably just an ordinary vector function

OpenStudy (anonymous):

it's r(t) = <7x, sqrt(39-49x^2)> Find r dot r'(0)

jimthompson5910 (jim_thompson5910):

ok

jimthompson5910 (jim_thompson5910):

so r'(t) = derivative of r(t)

OpenStudy (anonymous):

but that can't be tho... cuz the answer would be 49x... which it wont accept

OpenStudy (anonymous):

yeah

jimthompson5910 (jim_thompson5910):

so derive each component

OpenStudy (anonymous):

-49x / 2 sqrt ( 39 - 49x^2)

jimthompson5910 (jim_thompson5910):

to get r'(t) = <7, (-49*x)/sqrt(39-49*x^2) >

OpenStudy (anonymous):

but it doesn't really matter tho bc you do r'(0), which makes the y component = 0

OpenStudy (anonymous):

u are missing a 1/2 in the y component, but yeah that's what i got

jimthompson5910 (jim_thompson5910):

So r'(0) = <7, 0 >

jimthompson5910 (jim_thompson5910):

the 2's cancel

OpenStudy (anonymous):

yeah, then <7,0> dot <7x, sqrt(39 - 49x^2> right?

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

which would come out 49x

OpenStudy (anonymous):

the program says invalid answer format when i plug that in

jimthompson5910 (jim_thompson5910):

are you sure it's r'(0)?

jimthompson5910 (jim_thompson5910):

seems too easy to be zero

OpenStudy (anonymous):

positive

jimthompson5910 (jim_thompson5910):

can you take a screenshot of the problem?

OpenStudy (anonymous):

yeah, it litterally says r dot r'(0)

OpenStudy (anonymous):

sure 1 sec

OpenStudy (anonymous):

OpenStudy (anonymous):

shouldn't it say r(t) dot r'(0) tho? er i guess that doesn't matter

OpenStudy (anonymous):

grrr i hate these stupid online programs that they make us use. The problems are so simple, yet you have to waste sooo much time trying to use the program

OpenStudy (anonymous):

was thinking maaaybe the r meant magnitude? it kinda works out

OpenStudy (anonymous):

t's cancel out and you are left with 39

jimthompson5910 (jim_thompson5910):

yeah idk, programming error i guess

OpenStudy (anonymous):

not sure if you multiply or add from there tho

OpenStudy (anonymous):

eh 3 tries, gonna try it

OpenStudy (anonymous):

faaack

jimthompson5910 (jim_thompson5910):

it's odd how they refer to it as r dot r'(0) and not r(t) dot r'(0)

OpenStudy (anonymous):

yeah that's what i was thinking. bc there are other problems where they say r(t)

jimthompson5910 (jim_thompson5910):

does it give you any hints?

jimthompson5910 (jim_thompson5910):

maybe they're thinking of the unit vector?

OpenStudy (anonymous):

no hints available

OpenStudy (anonymous):

eh no way tho, why would they leave it up to interpretation

jimthompson5910 (jim_thompson5910):

idk

jimthompson5910 (jim_thompson5910):

you'll just have to take it up with your teacher

jimthompson5910 (jim_thompson5910):

because that is the right answer

OpenStudy (anonymous):

yeah, no good. Alright, well thanks for the help. i do appreciate it

jimthompson5910 (jim_thompson5910):

k np

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