Is it possible to use the dot product with a vector and magnitude? ie. r dot |r|
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
do you just distribute?
OpenStudy (anonymous):
yes
jimthompson5910 (jim_thompson5910):
no, because x dot y is defined only when x and y are both vectors
OpenStudy (anonymous):
a vector times a scalar is distribution
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OpenStudy (anonymous):
right but a vector dot scalar is distribution?
jimthompson5910 (jim_thompson5910):
If the vector x = <a, b> and | x | = c for some scalar c, then
|x|*x = c*<a,b> = <ca, cb>
OpenStudy (anonymous):
so what would be the outcome of r dot r'(0)???
trying to figure out what r is because i know i have the right answer but this program we use says it isn't
OpenStudy (anonymous):
ahhhh so you can then
jimthompson5910 (jim_thompson5910):
r looks like a function in polar coordinates
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jimthompson5910 (jim_thompson5910):
or it's probably just an ordinary vector function
OpenStudy (anonymous):
it's r(t) = <7x, sqrt(39-49x^2)> Find r dot r'(0)
jimthompson5910 (jim_thompson5910):
ok
jimthompson5910 (jim_thompson5910):
so r'(t) = derivative of r(t)
OpenStudy (anonymous):
but that can't be tho... cuz the answer would be 49x... which it wont accept
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OpenStudy (anonymous):
yeah
jimthompson5910 (jim_thompson5910):
so derive each component
OpenStudy (anonymous):
-49x / 2 sqrt ( 39 - 49x^2)
jimthompson5910 (jim_thompson5910):
to get r'(t) = <7, (-49*x)/sqrt(39-49*x^2) >
OpenStudy (anonymous):
but it doesn't really matter tho bc you do r'(0), which makes the y component = 0
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OpenStudy (anonymous):
u are missing a 1/2 in the y component, but yeah that's what i got
jimthompson5910 (jim_thompson5910):
So r'(0) = <7, 0 >
jimthompson5910 (jim_thompson5910):
the 2's cancel
OpenStudy (anonymous):
yeah, then <7,0> dot <7x, sqrt(39 - 49x^2> right?
jimthompson5910 (jim_thompson5910):
yep
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OpenStudy (anonymous):
which would come out 49x
OpenStudy (anonymous):
the program says invalid answer format when i plug that in
jimthompson5910 (jim_thompson5910):
are you sure it's r'(0)?
jimthompson5910 (jim_thompson5910):
seems too easy to be zero
OpenStudy (anonymous):
positive
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jimthompson5910 (jim_thompson5910):
can you take a screenshot of the problem?
OpenStudy (anonymous):
yeah, it litterally says r dot r'(0)
OpenStudy (anonymous):
sure 1 sec
OpenStudy (anonymous):
OpenStudy (anonymous):
shouldn't it say r(t) dot r'(0) tho? er i guess that doesn't matter
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OpenStudy (anonymous):
grrr i hate these stupid online programs that they make us use. The problems are so simple, yet you have to waste sooo much time trying to use the program
OpenStudy (anonymous):
was thinking maaaybe the r meant magnitude? it kinda works out
OpenStudy (anonymous):
t's cancel out and you are left with 39
jimthompson5910 (jim_thompson5910):
yeah idk, programming error i guess
OpenStudy (anonymous):
not sure if you multiply or add from there tho
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OpenStudy (anonymous):
eh 3 tries, gonna try it
OpenStudy (anonymous):
faaack
jimthompson5910 (jim_thompson5910):
it's odd how they refer to it as r dot r'(0) and not r(t) dot r'(0)
OpenStudy (anonymous):
yeah that's what i was thinking. bc there are other problems where they say r(t)
jimthompson5910 (jim_thompson5910):
does it give you any hints?
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jimthompson5910 (jim_thompson5910):
maybe they're thinking of the unit vector?
OpenStudy (anonymous):
no hints available
OpenStudy (anonymous):
eh no way tho, why would they leave it up to interpretation
jimthompson5910 (jim_thompson5910):
idk
jimthompson5910 (jim_thompson5910):
you'll just have to take it up with your teacher
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jimthompson5910 (jim_thompson5910):
because that is the right answer
OpenStudy (anonymous):
yeah, no good. Alright, well thanks for the help. i do appreciate it