Mathematics
22 Online
OpenStudy (anonymous):
limits question! \[\lim_{t \rightarrow 0} \left[ 1\div t \sqrt{1+t} -1\div t \right]\]
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hero (hero):
rationalize
OpenStudy (anonymous):
find a common denominator and things should cancel
OpenStudy (anonymous):
thats two separate fractions right?
hero (hero):
yup
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
find a common denominator the usual way and it should work out
OpenStudy (anonymous):
please show me steps.
hero (hero):
I'm sleepy. I'm going to bed. QED will show you hopefully
OpenStudy (anonymous):
i will
OpenStudy (anonymous):
ok, gnight.
QED, thank you. :)
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OpenStudy (anonymous):
last one tho bcuz this is annoying to type out
OpenStudy (anonymous):
ok, thank you so much for all the help tho.
OpenStudy (anonymous):
you truly are a lifesaver.
OpenStudy (anonymous):
\[=(1-\sqrt{1+t})/t \sqrt{1+t} after combining terms\]
OpenStudy (anonymous):
then you rationalize
\[((1-\sqrt{1+t})/t \sqrt{1+t}) * (1+\sqrt{1+t})/(1+\sqrt{1+t}))\]
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OpenStudy (anonymous):
then u have only t left on top, which cancels the t on the bottom (DO NO MULTIPLY BOTTOM OUT)
OpenStudy (anonymous):
then just plug in 0 and youre good
should get.... 1/2
hero (hero):
frac{a}{b}
OpenStudy (anonymous):
thanks hero
OpenStudy (anonymous):
sorry, -1/2
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hero (hero):
It's a little tricky posting those with square roots, but you'll figure it out
OpenStudy (anonymous):
ok, thank you both
OpenStudy (anonymous):
np
hero (hero):
I didn't even do anything
OpenStudy (anonymous):
well you tried to help. so ty, that counts. :)