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find the vertex, line of symmetry and range, -x^2-4x-1
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\[\Huge \frac{-b}{2a}\]
I need someone to walk me thru
I think vertex(-2,3) line of symmetry x=-2
I didn't get that
let y=-x^2-4x-1 y=-((x+2)^2-3) so vertex is (-2,3) and it'll be symmetrical to line x=-2
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and range is (-infnity,3)
I don't see where you get -3 in your y=((x+2)^2-3)
take - common in expression and 3 and -3 in expression so y=-(x^2+4x+1+3-3) y=-(x^2+4x+4-3), so y=-((x+2)^2-3)
Where does +3 and -3 come from????
in any algebric expression ,if you add "a" and subtract "a" then it does not change the expression
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