How would I solve this? :)

Given: AB=x+7, BC=11, and BC=3x-8
(Drawing the pic) ^_____^

Question

How would I solve this? :)

Given: AB=x+7, BC=11, and BC=3x-8
(Drawing the pic) ^_____^

anonymous · Answer

|dw:1317057284778:dw|

anonymous · Answer

BC = 3x-8 , BC=11
ie  3x-8 = 11
x=(11+8)/3 
   = 19 / 3 = 6.33 
sub x in AB then we get AB= 6.33 +7 = 13.33

anonymous · Answer

is this u expected??

anonymous · Answer

No, I wasn't sure how to do it. I was just doing whatever came to mind. I got it wrong but I was wondering what the process was to solve it. :) Thank you, though. ^____^

hero · Answer

Are you sure you posted your question correctly?

hero · Answer

You have two BC values. Are you solving for x or are you solving for AC?

anonymous · Answer

?!?!? Omg no it's wrong!!!!! I'm sorry!!! Thank you, Hero!!!! x(

anonymous · Answer

Given: AB=x+7, BC=11, and AC=3x-8

hero · Answer

:D

anonymous · Answer

Ok, I fixed it. :)

hero · Answer

So AB + BC = AC

x+7 + 11 = 3x - 8

x + 18 = 3x - 8 

2x = 26

x = 13

hero · Answer

There we go

anonymous · Answer

So, x is 13?

hero · Answer

Yup

anonymous · Answer

:D Ok, thank you both for helping me. ^____^