Question

How would I solve this? :)

Given: AB=x+7, BC=11, and BC=3x-8
(Drawing the pic) ^_____^

Answer 1

BC = 3x-8 , BC=11
ie 3x-8 = 11
x=(11+8)/3
= 19 / 3 = 6.33
sub x in AB then we get AB= 6.33 +7 = 13.33

Answer 2

is this u expected??

Answer 3

No, I wasn't sure how to do it. I was just doing whatever came to mind. I got it wrong but I was wondering what the process was to solve it. :) Thank you, though. ^____^

Answer 4

Are you sure you posted your question correctly?

Answer 5

You have two BC values. Are you solving for x or are you solving for AC?

Answer 6

?!?!? Omg no it's wrong!!!!! I'm sorry!!! Thank you, Hero!!!! x(

Answer 7

Given: AB=x+7, BC=11, and AC=3x-8

Answer 8

:D

Answer 9

Ok, I fixed it. :)

Answer 10

So AB + BC = AC

x+7 + 11 = 3x - 8

x + 18 = 3x - 8

2x = 26

x = 13

Answer 11

There we go

Answer 12

So, x is 13?

Answer 13

Yup

Answer 14

:D Ok, thank you both for helping me. ^____^