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Mathematics 15 Online
OpenStudy (anonymous):

Is it possible for a linear operator T: R^2--> R^2 to satisfy T^2=T (that is the composition of T with itself equals T again) without having T=Z or T=I, if so give an example of such a linear operator T, if not prove that it is not

OpenStudy (anonymous):

what does T = Z mean?

OpenStudy (anonymous):

the zero operator, and T=I is the identity operator

OpenStudy (anonymous):

i assume T = I means T is the identity

OpenStudy (anonymous):

sure, put \[T(x_1,x_2)=(x_1,0)\] a projection in fact such a T with T^2=T is often called a "projection" even if it is not the one wrote

OpenStudy (anonymous):

*I wrote

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