If one side of a rectangle increases ar a rate of 2 m/s and the other side decreases at a rate
of 3 m/s, find the rate of change of the area when the first side is 4 m and the second side
is 5 m.

Question

hero · Answer

Now you're doing calculus?

hero · Answer

Oh, nevermind, lol. You were always doing calculus

hero · Answer

A = xy

A_t' = (dx/dt)y + x(dy/dt)

anonymous · Answer

area : oneside * otherside

darea = dx*y + dy*x
darea = 2*4 + 3*5 = 23

hero · Answer

A_t' = (2)4 + 3(5)

A_t' = 8 + 15 = 23m^2

hero · Answer

23m/s^2

hero · Answer

Only thing cool sector....you're taking the derivative with respect to time

anonymous · Answer

so 23 is the answer? thats all there is to it?

anonymous · Answer

i was trying to make it way more complicated.