Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
what is the question?
OpenStudy (anonymous):
Not enough info
OpenStudy (anonymous):
y intercept
OpenStudy (anonymous):
et x=0 and solve for y:
8y+3(0)=24
8y=24
y=3 (this is the y-intercept)
the graph intersects they-axis at the point (0,3)
OpenStudy (anonymous):
now i have a typo in the first line "et" should read "let" hahahah...
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
every point on the y-axis has x-coordinate 0, so that's why we let x=0 and solve for y when looking for y-ints
OpenStudy (anonymous):
thank u so much
OpenStudy (anonymous):
np
OpenStudy (anonymous):
-5y+2=-7x
OpenStudy (anonymous):
y-int?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
y-int: let x=0 and solve for y
-5y+2=-7x
-5y+2=-7(0)
-5y+2=0
2=5y
2/5=y (this is the y-int)
some teachers want it written as an ordered pair, i.e., the point (0, 2/5) the point where the graph crosses the y-axis
OpenStudy (anonymous):
y-int?
OpenStudy (anonymous):
thank u
OpenStudy (anonymous):
-4-2y=10x
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
-4-2y=10x
OpenStudy (anonymous):
y-int: let x=0 and solve for y
-4-2y=10(0)
-4-2y=0
-2y=4
y=-2 is the y-int; or as an ordered pair (0, -2)