parallel to the lines 5x+8y=-7, containing the point (5,2)

Question

anonymous · Answer

Rearrange equation so that  it is in slope intercept. Basically get y on one side, everything else on the other. You get:

$$y=(-5/8)x-(-7/8)$$

Recall the concept that two parallel lines have the same slope otherwise one is going to run over the other. Also recall point-slope form. We have slope. We have a point. Let's do this.

Point intercept is $$y_{2}- y_{1}=m(x _{2}-x _{1})$$

Slope is m. The first line's slope is -5/8. The point you are given is (5,2). Make those the  $$y _{1}   and  x _{1}$$.

Plug in to point intercept form. Take out the 2 subscript in the y and x. Multiply by m. Get y by itself. You get

$$y=(-5/8)x-(9/8)$$

anonymous · Answer

thanx