What is the derivative of:
sqrt((3x-1)/(2x+3))

Question

anonymous · Answer

$$\sqrt{(3x-1) / (2x+3)}$$
I got:
$$15/(2(2x+3)^{2}) * \sqrt{(2x+3)/(3x-1)}$$

anonymous · Answer

oh thats different than what i thought it was... give me a minute lol

anonymous · Answer

$$f \prime(x)= (1/2)((3x-1)/(2x+3))^{-1/2}*((3)(2x+3) - (3x-1)(2)/(2x+3)^{2})$$$$((3x-1)/(2x+3)^{2})$$

anonymous · Answer

i would use the quotient rule with this one and break it down into the equation of (3x-1)^(1/2)/(2x+3)^(1/2)  then use the quotient rule and power rule to find the answer.  my laptop is about to die so i can write my answer in about 30 min.

anonymous · Answer

$$=(1/2)((2x+3)/(3x-1))^{1/2} *( (6x+9-6x+6)/(2x+3)^{2})$$
$$=(1/2)((2x+3)/(3x-1))^{1/2} *( (15)/(2x+3)^{2})$$
$$=((15)/(2(2x+3)^{2}))*\sqrt{(2x+3)/(3x-1)}$$