Question

hey can you guys help me set up this problem please <3

a frame for a picture is 2in wide. the picture inside the frame is 4 inches longer than it is wide. if the area of the picture is 320 square inches, find the outside dimensions of the picture frame.

http://img23.imageshack.us/img23/4581/paintym.jpg

Answer 1

Let the Width of the picture is W, then length is W+4, we have area = 320 Sq inches. so W*(W+4)= 320.. Now that will give us W^2 +4W=320. or W^2 +4W-320=0. Solving for w , we get, W^2 + 20W-16W-320=0 or, W(W+20)-16(W+20)=0. or, (W+20)*(W-16)=0. So W= 16 or -20. since we cannot have negative length we ignore -20 and only use 16 which is the width and length is 20. Now add 4 inch on width (2 inch on each side) and 4 inches to length(2 inches on each side) to get the correct dimension for the frame. i.e width of frame is 20 inches and length is 24 inches.

one thing you did not put question correctly. The good thing is i saw the image

Answer 2

lolol i just typed down what my prof wrote word for word xD thanx for the help =]