Anybody up for some calc 2 question on center of mass?

Question

anonymous · Answer

Find the center of mass of the triangular region in the first quadrent between the circle x^2+y^2 equals 9. And the lines x=-3 and x=3

anonymous · Answer

Typo: between the lines  is x=3 and y=3

anonymous · Answer

Hint use geometry to find the area

anonymous · Answer

the area of the required region wil be the area of the square formed by the lines x=3 and y=3 (Minus) the area of the circle in the first quadrant...A$$A _{sq}=3^{2}$$  wheareas $$A _{circle}=\Pi3^{2}/4$$ then subtract these values

anonymous · Answer

but it is a triangluar region, not a square

anonymous · Answer

just draw the figure...you will understand my solution :-)

anonymous · Answer

could you help me draw this, i am having trouble picturing it

anonymous · Answer

I know the circle, but this triangular region, how to i draw it

anonymous · Answer

|dw:1317202910554:dw|

anonymous · Answer

oh, that is a square

anonymous · Answer

the shaded regioon is the required area...which is a subtraction of the area of the circle in the first quadrant and the "square formed by our two lines

anonymous · Answer

so, then to get the mass, i just multiply that area buy delta. Okay thank you for the help

anonymous · Answer

cheers man

anonymous · Answer

I subtracted both values and got: (36-9pi)/(4)

anonymous · Answer

put the value of pi as 3.14 then

anonymous · Answer

i get 1.935