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f(x)=(ax+b)/(cx+d), abcd are constants. If ad=bc, show that f is a constant function.
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oh here
we can do this quickly if we get to use calculus
yes we can
ok then take the derivative, say "oh look it is zero" and therefore your function must be a constant. would you like me to write it out?
if you have time thx
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\[f'(x)=\frac{(cx+d)a-(ax+b)c}{(cx+c)^2}\] \[=\frac{acx+ad-acx-bc}{(cx+d)^2}=\frac{ad-bc}{(cx+d)^2}\] and since \[ad-bc=0\] you get \[f'(x)=0\] for all x making f a constant
k thx dude
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