Question

please help solve:
4^(10x-10)=5^(5x-7)

Answer 1

start with
\[(10x-10)\ln(4)=(5x-7)\ln(5)\] and then do a bunch of algebra

Answer 2

\[\ln(4^{10x-10})=\ln(5^{5x-7})\]

Answer 3

last night: integrals out the yin yang
tonight : algebra for days

Answer 4

don't forget that whatever those numbers are,
\[\ln(4)\text{ and } \ln(5)\] are just constants

Answer 5

\[\ln(4) 10x-10 \ln(4)=\ln(5) 5x-7\ln(5)\]

Answer 6

what

Answer 7

put like terms together
put x terms on one side
and put constant terms on the other side

Answer 8

\[\10\ln(4)x-5\ln(5)x=10\ln(4)-7\ln(5)\]

Answer 9

now we can write left hand side as....

Answer 10

and finally
\[x(10\ln(4)-5\ln(5))=10\ln(4)-7\ln(5)\] divide to get ...

Answer 11

and then
\[x=\frac{10 \ln(4)-7 \ln(5)}{10\ln(4)-5\ln(5)}\]

Answer 12

lol

Answer 13

lol

Answer 14

goodnight

Answer 15

gnight

Answer 16

thanx again both of you =)