Question

(5-3i)-(2+4i)

(4-3i)(9+2i)

(squarerootof -25)^3



5i/3-i

Answer 1

u answer mine ill answer urs

Answer 2

Nobody wants to do your homework for you

Answer 3

first one is combining like terms. you get
\[(5-3i)-(2+4i)=5-3i-2-4i=3-7i\]

Answer 4

except maybe satellite

Answer 5

why not?

Answer 6

lol

Answer 7

first, the point of this website it to help people.

second, it is not my homework.

Answer 8

you multiply
\[(a+bi)(c+di)=(ac-bd)+(ad+bc)i\]

Answer 9

so
\[(4-3i)(9+2i) =(4\times 9+3\times 2)+(4\times 2-3\times 9)i\]
or
\[42-19i\]

Answer 10

\[\sqrt{-25}=5i\] so
\[(5i)^3=5^3i^3=125(-i)=-125i\]

Answer 11

and finally
\[\frac{5i}{3-i}=\frac{5i}{3-i}\times \frac{3+i}{3+i}=\frac{-5+15i}{10}\]

Answer 12

which you write in standard form as
\[-\frac{1}{2}+\frac{3}{2}i\]

Answer 13

so satellite wanna do mine

Answer 14

yeah why not

Answer 15

where is it?