Question

-9e^(7x) over 7x-3 find derivative!

Answer 1

\[\frac{-9e^{7x}}{7x-3}\]

Answer 2

use quotient rule and chain rule. quotient rule is
\[(\frac{f}{g})'=\frac{gf'-fg'}{g^2}\] with
\[f(x)=e^{7x},f'(x)=7e^{7x},g(x)=7x-3,g'(x)=7\] and you can multiply by that annoying -9 at the end

Answer 3

you get
\[-9\times\frac{(7x-3)\times 7e^{7x}-e^{7x}\times 7}{(7x-3)^2}\]

Answer 4

you didnt finish the other one

Answer 5

what other one?

Answer 6

the problem that I posted

Answer 7

i can't find it. link

Answer 8

http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e83dec60b8bc11dd551cf85

Answer 9

i already solved it but apparently is wrong

Answer 10

i wrote it out