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what is equivalent to the following equation y=x^2+4x+11
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the compressed form of it i would assume
add 4 and subtract 4 to compress it
add 4 where and subtract where?
y=x^2+4x+(4-4)+11 y=(x^2+4x+4)-4+11 y=(x+2)^2 +7
in other words, the method is generally refered to as "completeing the square" if you wanna read up on it
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So y=(x+3)^2+53 would be the same way?
if they want a different form, then that one would need to be expanded
(x+2) * (x+3) = x^2 +6x + 9 y = x^2 +6x + 9 + 53
Thanks
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