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if H(3)=1, H'(3)=3, F(3)=5, F'(3)=4, find (a) G'(3) if G(z)=F(z)*H(z)
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I assume you want to take the derivative of this, soo.... G(z)=F(z)*H(z) NOTE: []=PRIME [G(z)]=[F(z)](H(z))+(F(z))[H(z)] plug in the nubmers [G(3)]=(4)(1)+(5)(3) [G(3)]=19 I hope you can understand what I did there
\[G'(3) = 5* 3 + 1 * 4 = 15+4 = 19\]
Where did you find teh prime thingy?
Remember to use the product rule. I showed the work, but it must have gotten deleted. The "prime thingy" is just one '
Ohhh wait nevermind, I could have used '. LOLLL
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