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OpenStudy (anonymous):
How do you factor (p+q)^3-(p-q)^3?
Please explain, don't just give the answer.
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OpenStudy (jamesj):
First, do you know how to factor in general the expression:
a^3 - b^3
?
OpenStudy (anonymous):
(a-b) (a^2+a b+b^2)
OpenStudy (jamesj):
Correct. Now set a = p + q and b = ....
and apply your formula.
OpenStudy (anonymous):
Does b equal p-q? It got cut off
OpenStudy (jamesj):
I didn't say, on purpose. But that would seem to make sense, wouldn't it?
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OpenStudy (anonymous):
Ah I see.
OpenStudy (jamesj):
Happy factoring!
OpenStudy (jamesj):
Just make sure you check your signs as you go.
OpenStudy (anonymous):
I got 2 (3 p^2 q+q^3)
OpenStudy (jamesj):
Looks good to me, as there are lots of cancelations.
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OpenStudy (anonymous):
Thanks again.
OpenStudy (jamesj):
if we just calculated it out
(p+q)^3 - (p-q)^3
= p^3 + 3p^2q + 3pq^2 + q^3
-p^3 + 3p^2q - 3pq^2 + q^3
= 0 + 6p^2q + 0 + 2q^3
= 2(3p^2q + q^3)
OpenStudy (jamesj):
So, likes lots of this in mathematics, there's more than one way to skin a cat.
Anyway -- got to move on! Cheers.
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