Question

Volume, Shell Method: x+y=6,x=10-(y-2)^2; about x-axis

Answer 1

What's the easiest way to get the 2nd graph? I usually plug-n-chug but this one kinda sucks.

Answer 2

well in this case since you are taking it about x axis you are going to need it in dy

Answer 3

you have it in x=(y-2)^2 -10 form

Answer 4

which is a parabola form

Answer 5

what does the -2 do? shift or make it fat/skinny?

Answer 6

(y-k)^2+h

Answer 7

where (h,k) is your vertex

Answer 8

also you need to find intercepts

Answer 9

set them equal and solve

Answer 10

...will i have to complete the square?

Answer 11

nope you can pull a y out ... your intercepts should be 0 and 5

Answer 12

so those are your a to b

Answer 13

I'm still trying to draw it, LOL

Answer 14

the average of your inner radius will be y and your height will be the differences of your functions

Answer 15

yeah drawing is always a pain lol you know where the vertex is and you know they meet at both 0 and 5.... just find points to graph the x=6-y graph and make a parabolaconnecting them lol

Answer 16

so (h,k) is 10,-2? x,y? or y,x?

Answer 17

oh it's (10,2)

Answer 18

yep

Answer 19

because in reality it's a -(y-2)^2+10

Answer 20

so it should look like this sorta