Question

simplify; Log3 9x^2-Log3 7xy= Log3 9x/7y???

Answer 1

\[\log_{3} (9x^2)-\log_{3}(7xy)=\log_{3}(9x/7y)\]
???? is the expression?

Answer 2

no the term after the = is my answer

Answer 3

it looks good to me

Answer 4

agreed

Answer 5

really???? wow

Answer 6

how did u get this answer?

Answer 7

i used the logarithm rule for subtraction

Answer 8

9x^2/7xy
=9x/7y

Answer 9

logx-logy=log(x/y)

Answer 10

this is the subtraction rule

Answer 11

logarithmic properties:
\[\log(ab)=\log(a)+\log(b)\] and
\[\log(x^n)=n \log(x)\]

Answer 12

where log is with base 3

Answer 13

just make sure the bases of the logs are the same, or else those rules won't work.

Answer 14

so was i wrong???

Answer 15

No! you were right, I don't know what uzma did.