Question

find f''(pi/4) using the equation f(x)=csc(x). I got 0 but it is wrong. What am I doing wrong?

Answer 1

(csc(x))'=-csc(x)cot(x)

Answer 2

then take derivative again using product rule

Answer 3

then plug in pi/4

Answer 4

yea i did that and got 0 but its wrong :/

Answer 5

why don't you show your work

Answer 6

\[\text{Cot}\left[\frac{\pi }{4}\right]^2 \text{Csc}\left[\frac{\pi }{4}\right]+\text{Csc}\left[\frac{\pi }{4}\right]^3=3 \sqrt{2} \]

Answer 7

second derivative: csc(x)(cot^2x+csc^2x)