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Find the sum of 2 radical 6 and radical 24. A.4 square root 6 B.2 square root 30 C.2 square root 6+4 square root 3 i think its B
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\[2\sqrt{6}+\sqrt{24}\]
So, why do you think it's B?
cuz dont you add just the roots
Do you agree with this:\[\sqrt{4}\sqrt{6}+\sqrt{24}?\]
What happens when you multiply two radicals?\[\sqrt{4}\sqrt{6}=?\]
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dont they just cancel the root
\[\sqrt{4}\sqrt{6}=\sqrt{4\cdot6}=\sqrt{24}.\]Do you see that?
yes i do
What do we have now?\[\sqrt{24}+\sqrt{24}=2\sqrt{24}.\]Am I correct?
yes
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What about this?\[2\sqrt{4\cdot6}=2\sqrt{4}\sqrt{6}=2\cdot2\sqrt{6}=4\sqrt{6}.\]Did you follow?
oh okay i got it know
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