Q = mc delta t? and an example i did
sample weight=.7 grams
degree of water(celcius) before burning= 22 degrees
degrees of water after burning= 23 degrees

Question

anonymous · Answer

please answer

nebi · Answer

what do you want to know?
$$-\xi \leftarrow \sqrt{\cos^{-1} \left[\begin{matrix}? & ? \ ? & ?\end{matrix}\right]}$$

p.s. I just wanted to test out the equation tab. It has nothing to do with the question

anonymous · Answer

umm, i just need to know if im doing it right. i did the equations, and im pretty sure a single peice of dog food does not have like, 200 Calories

anonymous · Answer

$$Q=MC \Delta T$$

nebi · Answer

Q = m*c*(delta T)
Q = heat energy
m = mass
c = specific heat
delta t = change in temperature (= final - initial temp)

Remember, in a closed system, heat gained by one thing equals the heat lost by another.

anonymous · Answer

its all multiplied right?

nebi · Answer

yea. as far as i know, you did it right, the equation is correct.

anonymous · Answer

....s single peice of puppy fod has like 354 Calories!?!?!?!?

nebi · Answer

What is the change in the temperature