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Mathematics 20 Online
OpenStudy (anonymous):

use the definition to the derivative of : f(z)=(2z-i)/(z-2i) at z=-i .

OpenStudy (anonymous):

.......of the derivative? or what...?

OpenStudy (jamesj):

Writing down the difference quotient we talked about earlier [f(z)-f(-i)]/(z+i) we have \[\frac{(2z-i)/(z-2i) - (-3i)/(-3i)}{z+i}\]

OpenStudy (jamesj):

convince yourself that is correct, then simplify, and you'll find that taking the limit as z --> -i is easy.

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