Question

integrate of -9t*e^-t dt can u help plz

Answer 1

Use integration by parts method!

Answer 2

integral (f dg) = f g- integral (g df), where
f = t, dg = e^(-t) dt,
df = dt, g = -e^(-t):

Answer 3

ok then ?

Answer 4

All you need to do is plug the values of f and g into their relation given, which gives a function and another integral to calculate.

Answer 5

ok let me try it but what u get for the answer

Answer 6

= 9 e^(-t) t-9 integral e^(-t) dt

Answer 7

i dont remember the equation of part integration

Answer 8

I hope you know how to integrate e^(-t) dt :)

Answer 9

ya is just -e^(-t)

Answer 10

= 9 e^(-t) (t+1)+constant

Answer 11

is that right ?

Answer 12

i didnt get how u get 9 e^(-t) (t+1)+constant

Answer 13

= 9 e^(-t) t+9 e^(-t)+constant
= 9 e^(-t) (t+1)+constant