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integral 1 to 9 1/2x dx is log right?
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i.e 1/x dx?
yes, integral of 1/x is log(x)
so ie log 2x?
No, log(x)/2 (constant stays out of integral)
ok so 1/x is logx but since there is 2 i keep that in the denominator?
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can you help me with this
yes, you can take it as 1/2 (constant) & stays as it is. you can take it out from integral too 1/2 integral (1/x dx)
ok so 1/x = log x correct? and since 1/2x =logx /2?
so i would have to log x/2 dx?
1/2(log 9 - log 1)
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ooo ok i see...thanks
i looked into the answer it says ln3...how would i go by caluating without calculaor?
1/2(ln 9 - ln 1) 1/2(ln 9) (ln 1 = 0) ln sqrt(9) ln 3
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