On average there are four traffic accidents in a city during one hour of rush-hour traffic. Use an appropriate distribution to calculate the probability that in one such hour there are (a) No accidents (b) At least 6 accidents
what would be the appropriate distribution? normal, poisson, geometric, Fdist, etc ...
Normal
ok, and would our mean be 4 and our standard distribution be 1 ? or is there some other way to find thoe?
I guess so if that's the literal meaning that the question states. I don't really see another way so yeah
"i guess" doesnt fill me with confidence :) trying to interpret the wordy into math is the trick here .. and i have my doubts if im reading it right
Well I'm the one asking the question so do you think I'm filled with confidence? Assuming that the horrible translation of average is the mean, then yes, that's what the question is saying.
|dw:1317578043601:dw|
that doesnt feel right to me
It wouldn't look like that, it would look like this if it's normal |dw:1317578176187:dw|
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