Question

Factor.

x^2+2x-4=0

Answer 1

oh heck no
sleeping again saifoo?

Answer 2

what?

Answer 3

\[x=\frac{-2 \pm \sqrt{2^2-4(1)(-4)}}{2(1)}\]

Answer 4

It says to Factor! :/

Answer 5

i plug a=1, b=2, c=-4 into the quadratic formula

Answer 6

It is factorable. Ask myininaya

Answer 7

\[x^2+2x-4=0\]
\[x^2+2x=4\]
\[(x+1)^2=5\]
\[x+1=\pm\sqrt{5}\]
\[x=-1\pm\sqrt{5}\]

Answer 8

yes it is factorable lol

Answer 9

i you want to factor you can write
\[(x-(-1+\sqrt{5}))(x-(1-\sqrt{5}))\]

Answer 10

x^2+2x-4=0

x^2+2x+(1-1)-4=0

(x^2+2x+1)-1-4=0

(x+1)^2 -5=0

x = B-1

B = +- sqrt(5)

Answer 11

does no one watch football? i mean i don't, but it is sunday afternoon after all.

Answer 12

whats a football?

Answer 13

\[(x + 1 + \sqrt{5})(x + 1-\sqrt{5})\]

Answer 14

soccer?

Answer 15

soccer=football?

Answer 16

what it was, was football
http://www.youtube.com/watch?v=-z3XvZ-lh7I

Answer 17

fail. Think American Football

Answer 18

so how would i write it? in factor terms?

Answer 19

I just wrote it out for you in factor terms

Answer 20

@molls i wrote it out in factored form above

Answer 21

as did hero

Answer 22

you cant write it out in factored form; its an ideal that cannot be symbolized .... like pi lol

Answer 23

hero's does not equal satellite's expression though

Answer 24

you have a point there.

Answer 25

use my formula on the pdf i have provided you with

Answer 26

I think my factored form is right b is positive, not negative

Answer 27

yeah because i am wrong i should have written
\[(x-(-1+\sqrt{5}))(x-(-1-\sqrt{5}))\]

Answer 28

myininaya showed me

Answer 29

@moll point is you find the roots (zeros)
\[r_1,r_2\] and then factor as
\[(x-r_1)(x-r_2)\]

Answer 30

what is was, was football

Answer 31

\[(x+\frac{b+\sqrt{b^2-4ac}}{2a})(ax+\frac{b - \sqrt{b^2-4ac}}{2})=0\]

Answer 32

gj hero