Question

What are the smalelst values of x that would give whole numbers as a result?

13x+1/3

Answer 1

actually (13x+1)/3

Answer 2

define small

Answer 3

Well, the answers are 2 . 5 and 8

Answer 4

so you want
\[\frac{13x+1}{3}\] to be a whole number is that correct?

Answer 5

2, 5

Answer 6

Yes please

Answer 7

in other words
\[13x+1\] must be a multiple of 3 right? try x = 2

Answer 8

i spose whole number is a postive integer

Answer 9

I need the 3 smallest numbers

Answer 10

I need the 3 smallest numbers

Answer 11

Yep positive

Answer 12

I need the 3 smallest numbers

Answer 13

Is there any ,ethod of doing it though? Except for trial and error?

Answer 14

I need the 3 smallest numbers

Answer 15

*method

Answer 16

for x = 2 you get
\[13\times 2+1=27\]

Answer 17

well once you have x = 2 the rest should be clear. and x = 2 was not too hard to find

Answer 18

13x+1 = 1,3,6,9,12, etc

Answer 19

err... not 1 but i menat 0 if im thinking right

Answer 20

if x = 2 works that means \[13\times 2+1\] is divisible by 3, in fact it is
\[3\times 9\] therefore since 3 and 13 are relatively prime the next one what will work is
\[2+3=5\] try it

Answer 21

\[\frac{13x+1}{3}=N\]
\[13x+1=3N\]
\[13x=3N-1\]
\[x=\frac{3N-1}{13}\]
where x is any whole number

Answer 22

ugh ... where N is any whole number

Answer 23

I need the 3 smallest numbers

Answer 24

hmmm

Answer 25

I need the 3 smallest numbers

Answer 26

Thanks both of you !!

Answer 27

yep