An experiment consists of rolling two fair(not weighted) dice and adding the dots on the two sides facing up. Each die has the number 1 on two opposite faces, the number 2 on two opposite faces, and the number 3 on twoopposite faces.

Compute the probability of obtaining the indicated sums in problem.

41) 4

Question

An experiment consists of rolling two fair(not weighted) dice and adding the dots on the two sides facing up. Each die has the number 1 on two opposite faces, the number 2 on two opposite faces, and the number 3 on twoopposite faces.

Compute the probability of obtaining the indicated sums in problem.

41)  4

anonymous · Answer

adding the dots on the two sides facing up? is that how those things work?

anonymous · Answer

there are a total of 36 possible outcomes, just like with regular dice.  if you count, you will see that 12 of them give a  total of 4, so your answer is 
$$\frac{12}{36}=\frac{1}{3}$$

anonymous · Answer

the rest can also be obtained by counting.  the probability you get a sum of 2 is 
$$\frac{4}{36}$$ likewise for a sum of 6
and the probability you get a sum of 3 and the probability you get a sum of 5 is 
$$\frac{8}{36}$$