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Differential Equations home work problem. Solve the initial value problem of 2y''-3y'=0 if y(-2)=3 , y'(-2)=0
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I think I've got the answer I just want to check what I've got with some one else that knows how to do this
y(x)=3
That's what i was getting too I just thought that was a little weird iunno lol. Just making sure i wasn't doin it wrong.
y(x)=2/3 c_1 exp(3x/2) + c_2
Could you explain how you got that general solution? I end up with just c1+c2e^(3/2)t
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you can choose coefficients suitably to cancel. 2/3 c_1 & c_1 are equivalent
So you basically do that so that it's easier when you take derivatives?
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