Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Differential Equations home work problem. Solve the initial value problem of 2y''-3y'=0 if y(-2)=3 , y'(-2)=0

OpenStudy (anonymous):

I think I've got the answer I just want to check what I've got with some one else that knows how to do this

OpenStudy (anonymous):

y(x)=3

OpenStudy (anonymous):

That's what i was getting too I just thought that was a little weird iunno lol. Just making sure i wasn't doin it wrong.

OpenStudy (anonymous):

y(x)=2/3 c_1 exp(3x/2) + c_2

OpenStudy (anonymous):

Could you explain how you got that general solution? I end up with just c1+c2e^(3/2)t

OpenStudy (anonymous):

you can choose coefficients suitably to cancel. 2/3 c_1 & c_1 are equivalent

OpenStudy (anonymous):

So you basically do that so that it's easier when you take derivatives?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!