Question

Can you explain how to find the x-intercept in the equation: y=x^2-12x+39 In detail pleaaasse/

Answer 1

The graph of this relation crosses the x-axis when y = 0.
That is, when
x^2 - 12x + 39 = 0.

making sense so far?

Answer 2

I think there's a problem there.

Answer 3

Yeah, it's complex

Answer 4

In your calculations: b^2 - 4ac = 144 - 156 < 0

Answer 5

As you can see I figured it out already

Answer 6

I didn't do it the conventional way though. I'm just saying that because you assumed that I used the quad formula

Answer 7

lol. After I pointed out to you there was a problem. But ok.

Answer 8

It's all good James.

Answer 9

Who cares what method you use. If b^2 - 4ac is negative, there are no real roots.

Answer 10

Simon, why do even comment on the matter? I didn't use the quad formula at all.

Answer 11

No part of it