Can you explain how to find the x-intercept in the equation: y=x^2-12x+39 In detail pleaaasse/

Question

Can you explain how to find the x-intercept in the equation:  y=x^2-12x+39   In detail pleaaasse/

anonymous · Answer

The graph of this relation crosses the x-axis when y = 0.
That is, when
x^2 - 12x + 39 = 0.

making sense so far?

jamesj · Answer

I think there's a problem there.

hero · Answer

Yeah, it's complex

jamesj · Answer

In your calculations: b^2 - 4ac = 144 - 156 < 0

hero · Answer

As you can see I figured it out already

hero · Answer

I didn't do it the conventional way though. I'm just saying that because you assumed that I used the quad formula

jamesj · Answer

lol.  After I pointed out to you there was a problem.  But ok.

hero · Answer

It's all good James.

anonymous · Answer

Who cares what method you use.  If b^2 - 4ac is negative, there are no real roots.

hero · Answer

Simon, why do even comment on the matter? I didn't use the quad formula at all.

hero · Answer

No part of it