HELP ME \[1-3a^2+3a^4-a^6\]
we have to factorize 1-3a^2+3a^4-a^6
ooooh this looks like fun, lemme grab a pencil and some paper
factor it completely?
yes i think it can be solved through (a-b)^3
i meant this is in the form of a^3-b^3-3ab(a-b) that is (a-b)^3
k give me a sec, i have to write all this crap down when i work through it
Kush I came up with -(a-1)^3 * (a+1)^3
lemme go back and check my work again though
did u mean \[(1-a)^3(1+a)^3\]
I got \[-(a^2 - 1)^3\]
Damn, which is equivalent to what you got
yeah, thats the answer my bf came up with. But I told him I was still correct b/c it's the same as my answer haha.
the answer it is showing is \[(1-a)^3(1+a)^3\]
What do you mean by "IT"?
where did your negative sign go?
Hehehe women are always right ;)
can u say the solution any1
lol not really >_<
Well, the solution is already there, in two different, albeit correct, forms
but the answers are different
And yet they are both equivalent
lol yes, he's very right. there both equivalent, so you got twice what you were looking for! =3
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