Question

find the derivative of (x^2)cosx + 4sinx

Answer 1

To find the derivative of\[x^2cosx\]You can just do the multiplication rule. So, let\[u=x^2,v=cosx\]Then\[{{du}\over{dx}}=2x,{{dv}\over{dx}}=-sinx\]So the derivative is \[2xcosx-x^2sinx\]

Answer 2

Then just derive \[4sinx\]which will be\[4cosx\]

Answer 3

So putting it all together, you will get a final answer of \[2xcosx-x^2sinx+4cosx\]