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Solve the equation using the square root method.
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\[\sqrt{x+1}=4\]
Okay, so we can square both sides to cancel the radical on the left : \[\left( \sqrt{x+1} \right)^{2}=4^2\] which gives us x+1=16 take the 1 across by subtraction and boom! x=15
i dont know whats sqrt method but this can be olved by squaring both sides x+1=16 x=15
Oops wrote it wrong
Nvm. Thank you so much!
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