Question

Pre-Calc :

I've been looking at my test that I got back today, and I'm not sure how i got this one wrong.

The function is g(x) = abs(x) if x less than or equal to 0, and x^2 if x is greater than 0.

The problems I got wrong were

g(-2.3) and g(4.5), and I'd appreciate if someone answered these two with explanation :)

Answer 1

Well, we know that g(x) is a peace-wise function so let's state that here..
g(x) = abs(x) | x <= 0
g(x) = x^2 | x > 0

so part a)
We know that x = -2.3, therefore we use the first case where x <= 0 and say
g(-2.3) = abs(-2.3) = 2.3

and part b)
We know that x = 4.5, and thus use the second case where x > 0 and say
g(4.5) = (4.5)^2 = 20.25

Let me know if you don't understand.

Answer 2

Ohhhh Thank you! I plugged in -2.3 to x^2 and the 4.5 to abs(x).. Stupid mistake x_x.. Thank you for the explanation! :)