the ratio of females to males on a particular flight was 2 : 3. Females represented five more than 1/3 of all people aboard. how many people were on that flight
i think i just gave you the two equations and you deleted it
im so sorry i guess i didnt see it
A15 b.25 c.30 d40 e75
\[\frac{f}{m}=\frac{2}{3}\] \[f=5+\frac{1}{3}(f+m)\] do you see how i got these two equations?
yeah i see
ok solve the first equation for f by multiplying both sides by m then substitute that f into the second equation and solve for m
how?
have you solve the first equation for f yet?
im not sure how to get f
\[\frac{f}{m}=\frac{2}{3}\] multiply both sides by m \[f=\frac{2}{3}m\]
now plug this into the second equation and solve for m
5+1/3(2/3m) like that?
\[\frac{2}{3}m=5+\frac{1}{3}(\frac{2}{3}m+m)\]
thank you
\[\frac{2}{3}m=5+\frac{1}{3}(\frac{2}{3}m+\frac{3}{3}m)\] \[\frac{2}{3}m=5+\frac{1}{3}(\frac{5}{3}m)\] \[\frac{2}{3}m=5+\frac{5}{9}m\] \[\frac{2}{3}m-\frac{5}{9}m=5\] \[\frac{6}{9}m-\frac{5}{9}m=5\] \[\frac{1}{9}m=5\] so m=45 right? but we want to know f+m so we need to know f too right?
remember \[f=\frac{2}{3}m=\frac{2}{3}(45)=2(15)=30\]
so f+m= what?
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