Question

f(x) = -0.6 x^2+1.2 x+1.4
What is the Domain & Range?

Answer 1

didn't we just do this damned problem?

Answer 2

And please i want the COMPLETING SQUARE FORM STEPS.

Answer 3

haha, yes we did.

Answer 4

so you want all the steps, not the
\[-\frac{b}{2a}\] shortcut?

Answer 5

i have to show it..

Answer 6

ok fine. here we go.
1) factor out the leading coefficient from the first two terms and get
\[f(x)=-.06(x^2-2x)+1.4\]

Answer 7

2) then take half the middle term, which is -1, square it, get 1, and make sure that you have what you start with because you are not in fact adding 1 but (by the distributive law) subtracting -.6, so you have to add it back
\[f(x)=-.6(x^2-2x+1)+1.4+.6\]
\[f(x)=-.6(x^2-2x+1)+2\]

Answer 8

3) write as a perfect square
\[f(x)=-.6(x-1)^2+2\]

Answer 9

THanks! :)

Answer 10

You are the BOMB.

Answer 11

4) now the range, max, and vertex are displayed to see
vertex
\[(1,2)\] max : 2
range
\[(-\infty,2)\]

Answer 12

5) don't ask any more of these damned decimal questions!

Answer 13

6) Alright sir, that's why i shot that one and made another(easy) one.
;)

Answer 14

=)

Answer 15

Where is DOMAIN? :O

Answer 16

domain of a polynomial unless otherwise specified is all real numbers

Answer 17

Aint range gonna be:
(-infinity, 2]

Answer 18

what did i write?
oh yes, closed, you are right i wrote open. i am wrong and you are right

Answer 19

lol. thanks again.