1.20x+2.50y=300 List 3 possible combinations.
Solve for y=STUFF and then plug values in for x and get your y values which gives you pairs. Also, didn't you already ask this question?
Write them as coordinates or something like that
yes, you should probably right them as coordinates.
Do what agreene said: choose a value for either x or y and then solve for the other variable. I will write it in standard form first 12x + 25y = 3000 Now I will write it in another form:\[y = -\frac{12}{25}x+120\] I can now select points for x, and evaluate y. (0,120), (1,119.52),(2,119.04)
wouldnt a coordinate be 250,0
Yes (250,0) is contained by that function.
I got (120,0) (250,0) and I can't figure out the last one
(120,0) is not a valid answer. Please look at what I said to start this, and what agdgdgdgwngo was gracious enough to solve for you.
I mean 0,120
Okay sorry
(0,120) yes, that is valid. As is (pi,120-12pi/25)
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