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If y = x^2 + 2 / x^2 - 2 find dy/dx
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y'= 2x - 4/x^3
What formula did you use?
Quotient rule should do the job...
quotient rule \[y'=\frac{2x(x^2-2)-2x(x^2+2)}{(x^2-2)^{2}}\]
is your question :\[y=\frac{(x^2+2)}{(x^2-2)}\]
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yes it is, thanks for the help
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