from a standard deck of playing cards, what is the probability that the second card drawn is a Q of hearts?

Question

turingtest · Answer

(1/52)(1/51)???? no, can't be...

anonymous · Answer

If the first card drawn was a Q of hearts, then the probability that the second card drawn is 0

turingtest · Answer

ha ha, true

amistre64 · Answer

thats correct for one scenario :)

amistre64 · Answer

turning is correct for another scenario; whats the third scenario?

anonymous · Answer

So we must find the probability that the first card drawn was not a queen of hearts, given that the second card drawn was a queen of hearts!

turingtest · Answer

if agdgdgwngo is right wouldn't that be (51/52)(1/51) ?

amistre64 · Answer

maybe, but im not quite sure

anonymous · Answer

Let's run a simulation to find out

amistre64 · Answer

how about this one:  what is the probability that the 2nd card is a Qh if the first card is simply drawn and laid to the side without looking at it?

anonymous · Answer

it is 1/51 * something

phi · Answer

I   would argue that the Q of H is equally likely to be in any of 52 "slots".  So the probability of being in a specific slot, e.g. 2nd, is 1/52

turingtest · Answer

1/51 eh?
or is it still 1/52 (which my earlier answer suggests)

amistre64 · Answer

yes, 1/52 is the probability of that last one

turingtest · Answer

(51/52)(1/51) =1/52
I was right!

anonymous · Answer

yeah

anonymous · Answer

TuringTest passes the test

turingtest · Answer

Sweet

turingtest · Answer

got the idea from you though agdgdgdgwngo

anonymous · Answer

what idea?

turingtest · Answer

you said 
"So we must find the probability that the first card drawn was not a queen of hearts, given that the second card drawn was a queen of hearts!"
which made me think the odds of the first card not being QH=51/52, odds of second card being QH=1/51
therefor (51/52)(1/51) like you said