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Mathematics 14 Online
OpenStudy (anonymous):

In how many different ways can I arrange the following lists? a) ABCDEFGHIJ b) ABCDEFGHII c) AAAAABBBBB

OpenStudy (anonymous):

a) I can rearrange that into 10! different lists, including the original arrangement. b) one element, I, is repeated twice, I find the ways that I can rearrange II, which is 2!. Now I can rearrange ABCDEFGHII in 10!/2! ways

OpenStudy (anonymous):

which is 1814400

OpenStudy (anonymous):

c), A and B are both repeated five times each. I can rearrange AAAAA 5! times, and BBBBB 5! times. Therefore, I can rearrange AAAAABBBBB 10!/(5! * 5!) times, which is 252

OpenStudy (anonymous):

Check my answers

OpenStudy (anonymous):

I am sorry, I don't have time to help now. :( I couldn't remember the approach exactly, and used all my time to catch up on how to do and left no time to do it!

OpenStudy (anonymous):

I can check later if no one else does it for you

OpenStudy (anonymous):

by the way; C is correct

OpenStudy (anonymous):

lets check for that last one. AABB, how many ways can I arrange that (easier) list? AABB ABAB ABBA BAAB BABA BBAA which is 4!/(2! * 2!) = 3 * 2 = 6 ways

OpenStudy (anonymous):

I feel enlightened

OpenStudy (anonymous):

a) 10! b) 10!/2! c) 10!/(5!5!) I agree with all your answers (but you didn't need me to tell you that!).

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