Question

I still need help on this equation 3y-2(y-1)/6=-1 all of the equation is over 6.

Answer 1

y=-6

Answer 2

3y-2(y-1)
--------- =-1
6

clear parenthesis
3y-2y+2
--------- =-1
6
combine similar terms
y+2
----- =-1
6
Multiply both sides by 6
y+2=-6
add -2 to both sides.
y=-8

Answer 3

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Answer 4

well, do I multiply the 2 by 6 as well?

Answer 5

id say no; the multiplying by 6 creates a condition such that 6/6 = 1

Answer 6

also known as "canceling" out, or clearing the fraction

Answer 7

so it's 6y+2=-6?

Answer 8

\[\frac{y+2}{6}=-1\]
\[\frac{6(y+2)}{6}=-1(6)\]
\[\frac{6}{6}(y+2)=-6\]
\[1(y+2)=-6\]
\[y+2=-6\]

Answer 9

does that make sense?

Answer 10

Thanks a lot! Makes much more sense! :D